(x+7)(x^2+3x-40)=0

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Solution for (x+7)(x^2+3x-40)=0 equation: 


Simplifying
(x + 7)(x2 + 3x + -40) = 0

Reorder the terms:
(7 + x)(x2 + 3x + -40) = 0

Reorder the terms:
(7 + x)(-40 + 3x + x2) = 0

Multiply (7 + x) * (-40 + 3x + x2)
(7(-40 + 3x + x2) + x(-40 + 3x + x2)) = 0
((-40 * 7 + 3x * 7 + x2 * 7) + x(-40 + 3x + x2)) = 0
((-280 + 21x + 7x2) + x(-40 + 3x + x2)) = 0
(-280 + 21x + 7x2 + (-40 * x + 3x * x + x2 * x)) = 0
(-280 + 21x + 7x2 + (-40x + 3x2 + x3)) = 0

Reorder the terms:
(-280 + 21x + -40x + 7x2 + 3x2 + x3) = 0

Combine like terms: 21x + -40x = -19x
(-280 + -19x + 7x2 + 3x2 + x3) = 0

Combine like terms: 7x2 + 3x2 = 10x2
(-280 + -19x + 10x2 + x3) = 0

Solving
-280 + -19x + 10x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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